CBSE Central Teacher Eligibility Test (CTET) July Notification out 2019

Central Board of Secondary Education (CBSE) Delhi has published Notification for the Central Teacher Eligibility Test CTET July 2019. Other details like age limit, educational qualification, selection process, application fee and how to apply are given below.

Organization Name: Central Board of Secondary Education (CBSE)

CBSE Central Teacher Eligibility Test (CTET) July  Notification out 2019

Post Names: 
Primary Stage (Class I to V)
Secondary Stage (Class VI to VIII) 

Educational Qualification:
For Primary Stage (Class I to V): Senior Secondary with 50% marks & D.El.Ed/ B.El.Ed/ Graduation with B.Ed
For Secondary Stage (Class VI to VIII): Senior Secondary with B.A/B.Sc.Ed or B.A.Ed/B.Sc.Ed/B.A.Ed/ Graduation with D.El.Ed/ B.Ed

Application Fee:
For Single Subject:
General / OBC : 700/- 
SC / ST / PH: 350/- 

For Both Paper: 
General / OBC : 1200/- 
SC / ST / PH: 600/- 

How To Apply: Eligible & Interested candidates can Apply Via Online In Official website page at www.ctet.nic.in

Important Dates:
Starting Date of Online Application: 05-02-2019
Last Date to Apply Online: 05-03-2019
Last Date Fee Payment: 08-03-2019
Online Correction: 14-20 March 2019
Admit Card Available: June 2019
Exam Date: 07-07-2019

Important Links: 
Detailed Notification: Click Here
Syllabus: Click Here
Exam Cities: Click Here
Exam Schedule: Click Here
Apply Online: Click Here

For More Details: Click Here